Translating graphs..... to FRENCH!?!?!?!?

Physic Graphs Translated

During the 1^st sec, there was no change in the distance; therefore there is a velocity of zero. From the 1^st to 3^rd sec, there was a constant speed of 1.7m/s east. During the 3^rd – 6^th sec, there was no change in distance; therefore, a velocity of zero. From the 6^th – 7.5 there was a velocity of -2m/s in the opposite direction, west. From then onward, there was no change in distance, therefore velocity as well. Since the velocity was always constant (horizontal line), the acceleration is 0.

From the beginning to the 3^rd second, there was a constant change of position heading west. The constant change was 0.5m/second. From the 3^rd second to the 4^th second, there was no change in distance, therefore a velocity of 0. From the 4^th second to the 5^th second, there was another constant change of position west at the rate of 1m/s. From the 5^th – 7^th second, there was no change in distance so there must be a velocity of 0. From the 7^th second to the end (10^th second) the distance goes to 3m in 3 seconds, which equates to 0.83333 m/s east. Throughout the chart, the velocity was always at a constant rate parallel to the x-axis, therefore the acceleration throughout is 0.

There is a velocity of 0 up to the 2^nd second. From the 2^nd second to the 5^th second, there is a velocity of 0.5m/s. Since there is a constant velocity of 0.5m/s, the distance will increase from 0.5m on the first second, all the way to 1.5m on the 5^th second. From the 5^th second up to the 7^th second, there is a velocity of 0, and the distance does not change. At the 7^th second, there is a sudden velocity of -0.5m/s, which signifies a change of 0.5m/s in the opposite direction. Starting at 1.5m/s the distance will constantly decrease for 3 seconds. 3s x 0.5m/s = 1.5m. The final distance will be 1.5 m. The acceleration is still 0 because of the fact that the velocity stays at a constant rate: in the beginning, the velocity is 0, then the velocity stays at 0.5m/s, then changes back to 0, then finally stays at -0.5ms. Therefore there is no acceleration.

From the 1^st second to the 4^th second, there is a constant change of velocity. The velocity increases by 1/8 or 0.125m/s every second. The distance can be calculated by measuring the velocity of each second and adding them together. At the 4^th second all the way to the 6^th second, there is a constant velocity of 0.4m/s. All you do is add 0.5m/s to the distance every second. At the 6^th second, the velocities reverses from going east to going west at a rate of 0.4m/s for 3 seconds. Since you are moving in the opposite direction, you subtract 0.4m from the distance every second. Finally from the 9^th second to the 10^th second, there is a velocity of 0 and the distance does not change. Since there is a constant change in the velocity, the slope of the change becomes the acceleration. The slope of the constant rise is 2; therefore the acceleration is 2m/s². From there onward, the velocity is either 0 or has a slope of 0 therefore there is no acceleration.

From the start to the 2 and 3/4^th of a second, there is a constant rise in distance. The constant rise becomes the velocity, of 0.1666. From that point to the 6 and 1.2th of a second, there is no change in distance, therefore a velocity of 0. Finally, from the 6 and 1/2th of a second to the end (10^th second) there is a constant rise of distance at a rate of 0.4m/s, which is the velocity. The acceleration is still 0 because the velocity is either on the x-axis or parallel to the x-axis.

During and after the 6th second, the distance is the same as the acceleration

Though this graph may be slightly hard to distinguish, it is relatively easy. From the beginning to the 3^rd second, there is a constant velocity of 0.1666m/s, therefore an increase in the distance. From that point on till the 6 and a half second, there is a constant velocity of -0.1666m/s, which means that there is a decrease in the distance at a rate of 0.1666m every second. Finally, until the end there is a velocity of 0, which means that there is no change in distance. The acceleration may vary according to how you interpret it, but assuming that the slight curve is intentional, there is a slight acceleration of 0.3333m/s and acceleration again of 0.1666m/s. The first acceleration is in the negative region because the velocity is changing from positive to negative, therefore a slope downward. The left hand arrow pose shows that the acceleration must therefore be negative.

By: Kingeon Tsang